Please explain!
Thanks a bunch!
2007-10-18 08:09:55 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
ZnCl2 : H2 ==> 1:1 molar relationship
H2 MW = 2.0158 g/mole
3g H2 = 3 g * mole/2.0158 g = 1.49 mole
ZnCl2 MW = 136.29 g/mole
1.49 mole ZnCl2 = 1.49 mole * 139.29 g/mole = 207 g ZnCl2
2007-10-18 08:15:11 · answer #1 · answered by Dr Dave P 7 · 1⤊ 0⤋
Anhydrous ZnCl2 could nicely be arranged from zinc and hydrochloric acid. Zn + 2 HCl ? ZnCl2 + H2 the hydrogen interior the reactants is interior the ionic type, so because it relatively is why the question purely known because it as purely "hydrogen." The leftover Cl varieties bonds with Zn, which has oxidation state of +2
2016-12-18 11:04:59 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Atomic weights: Zn=65.4 Cl=35.5 ZnCl2=136.4 H=1 H2=2
3gH2 x 1molH2/2gH2 x 1molZnCl2/1molH2 x 136.4gZnCl2/1molZnCl2 = 204.6g ZnCl2
Although 3g H2 has only one significant figure. So the answer is 200g ZnCl2 to one significant figure.
2007-10-18 08:16:03 · answer #3 · answered by steve_geo1 7 · 1⤊ 0⤋
Give or take 10.
2007-10-18 08:12:23 · answer #4 · answered by Anonymous · 0⤊ 1⤋