chem help................................................................?

Question

Methanol, CH3OH, can be produced by the following reaction.

CO(g) + 2 H2(g) CH3OH(g)
Hydrogen at STP flows into a reactor at a rate of 19.0 L/min. Carbon monoxide at STP flows into the reactor at a rate of 25.0 L/min. If 5.55 g of methanol is produced per minute, what is the percent yield of the reaction?

%

show me how please. i have a test

Answer 1

CO(g) + 2 H2(g) ==> CH3OH(g)
Clearly H2 flow is the limiting flow.
theoretical production: (19.0L/22.4L)*32.04/2 = 13.6 g/min
the percent yield: 5.55/13.6 = 40.8%