chem help please.....................?

Question

2 NO2(g) --->N2O4(g)
If 36.4 mL of NO2 gas is completely converted to N2O4 gas under the same conditions, what volume will the N2O4 occupy?

please help. i need to understand how to do this for my test. the answer would be nice so i can check my answers.

Answer 1

N2 O4 will occupy half of 36.4 mL. That is 18.2 mL.

A fact in chemistry that you will need for solving this problem is that,
under similar conditions, same number of moles of any gas will occupy same volume.

So 1 mole of ANY gas will occupy 1 volume;
2 will occupy 2 volumes, etc.

Now in your problem, 2 moles of NO2 gas [2 NO2(g)] is forming 1 mole of N2O4 gas [N2O4(g)].

So, if 2 moles were occupying a volume of 36.4 mL, 1 mole will occupy half of that volume. That is half of 36.4 mL, which is 18.2 mL.

Answer 2

you see from the equation that you have 2 NO2 for 1 N2O4
So the number of mole is divided by 2. As under same conditions the volume is proportional to mole the volume is divided by 2 and 36.4/2= 18.2 mL

Answer 3

According to Lussac's law, ratio of volumes of reactants and products of chemical reaction is a whole number ratio under same condtions.
ratio volume of NO2: volume of N2O4=2:1
so volume of N2O4=volume of NO2/2
=36.4ml/2=18.2ml

Answer 4

steps in calculating the number of grams of NO2 gas in 6.03 L of NO2 gas at STP

Answer 5

---------------------2NO2 ---------> N2O2
Molecular W.---2[(14+(16x2)] (14x2)+(16x2)
Volume --------- 36.4 ?

36.4 x 60 = 92 x ?

? = 23.7mL