How do I calculate moles of electrons released?

Question

Given:
- Each mole of Fe(CN)6 (4-) loses exactly one mole of electrons in a reaction
- Once you know # of moles of electrons released, you know number of moles of electrons used to reduce...
- n(electrons) = n(Fe(CN)6 (4-))
- Moles after titrations I found were .0005 m, .000196 m

Does anyone know how I can find number of moles of electrons released? I have no idea where to start or what to consider to find the moles of electrons.

Thank you so much for your help :)

Given:
- Each mole of Fe(CN)6 (4-) loses exactly one mole of electrons in a reaction
- Once you know # of moles of electrons released, you know number of moles of electrons used to reduce...
- n(electrons) = n(Fe(CN)6 (4-))
- Moles of ^ after titrations I found were .0005 m, .000196 m.

Now what? What equation or ratio do I incorporate?? So does this mean that .0005 moles of electrons were released too?

I have no idea where to start or what to consider to find the moles of electrons.

Thank you so much for your help :)

Answer 1

You don't mention 0.0005 m or 0.0000196 m of what.

You treat the moles of electrons gained and lost the same as any atoms or ions in an equation. For example:

Na ===> Na+ + e- One mole of Na releases one mole of electrons.

Fe ===> Fe++ + 2e- Each mole of Fe releases two moles of electrons.

2F- ===> F2 + 2e- Every two moles of fluoride release two moles of electrons.

By the way, Fe(CN)6(41) ===> Fe(CN)6(3+) + e-

Answer 2

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Answer 3

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