how can i make (1+cosx)/(1-cosx) be equal to (cscx + cotx)^2 ???????????????????????????
2007-10-18 06:26:05 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply by (1+cosx)/(1+cosx) to get
(1+cosx)^2/[(1-cosx) (1+cosx)]=
(1+cosx)^2/sin(x)^2 = [(1+cosx)/sinx]^2
= (1/sinx + cosx/sinx)^2 = (cscx + cotx)^2
2007-10-18 06:36:17 · answer #1 · answered by mulla sadra 3 · 1⤊ 0⤋
(1+cosx)/(1-cosx) = (cscx + cotx)^2
[(1+cosx)(1+cosx)][(1-cosx))(1+cosx)]= (cscx + cotx)^2
[1+ 2cosx +cos^2x]/(1-cos^x) = (cscx + cotx)^2
[1+2cosx +cos^2x]/sin^2x = (cscx + cotx)^2
csc^2x +2cotxcscx +cot^2x = (cscx + cotx)^2
(cscx + cotx)^2 = (cscx + cotx)^2
2007-10-18 13:43:43 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
rationalise the identiy by (1+ cos x)
2007-10-18 13:34:52 · answer #3 · answered by prem 1 · 0⤊ 0⤋
i do not have a clue
2007-10-18 13:29:02 · answer #4 · answered by Anonymous · 0⤊ 1⤋