Oxalic solution?

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Oxalic acid, H2C2O4, reacts with the chromate ion in acidic solution as follows:
H2C2O4(aq) + CrO4-2(aq)------>CO2(g) + Cr+3(aq)
What is the molarity of the oxalic acid solution if 10.0mL of this solution consumes 50.0mL of 0.0350 M CrO4-2? Could you guys please show the work step by step? Thank you

2007-10-18 06:22:52 · 1 answers · asked by Sky N. 1 in Science & Mathematics ➔ Chemistry

1 answers

Let the oxalic acid solution be called XS. Let the chromate solution be called CS.

50.0mLCS/10.0mLXS x 0.0350molCrO4=/1000mLCS x 1molH2C2O4/1molCrO4= x 1000mLXS/1LXS = 0.175 mole H2C2O4 per L XS, which is molarity.

2007-10-18 06:51:38 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋