Please explain.?

Question

I am suppose to add and express my answer in simplest form x^2/x+10+9x-10/x+10 trust me when I say I am lost.

Answer 1

x²/x + 10 + 9x - 10/x + 10.....x²/x = x, so

x + 10 + 9x - 10/x + 10....combine like terms

10x + 20 - 10/x...factor out a 10

10(x + 2 - 1/x)

Answer 2

You cannot just multiply by x to eliminate it; this is an
expression to simplify, not an equation to solve
Is this what you mean?

x²/x + 10 + 9x - 10/x + 10

LCD = x

x²/x + 10x/x + 9x²/x - 10/x + 10x/x

(x² + 10x + 9x² - 10 + 10x)/x

(10x² + 20x - 10)/x

You could factor the numerator and get

[10(x² + 2x - 1)]/x

but this is not reducible, so it is not in a simpler form

For instance, 6/7 is in simplest form
You could factor the 6 and write (2*3)/7 but it doesn't
simplify it

Is this what you mean?

x²/(x + 10) + (9x - 10)/(x + 10)

(x² + 9x - 10)/(x + 10)

[(x + 10)(x - 1)]/(x + 10)

x - 1

Answer 3

x^2/x +10 +9x -10/x +10
x +9x +20 - 10/x
10x+20 -10/x
At this point, "gebobs" took the common factor out, to
get 10(x+2-1/x). This is a correct answer

My preferred technique is to put all terms over a common denominator so that they can be added.
Thus, 10x+20-10/x becomes
10x^2/x+20x/x-10x/x,
[10x^2+20x-10] /x
10[x^2+2x-1] /x

Ms Exclusive was correct to multiply all terms by x,
but there should then be a common denominator x.
Without this , her answer is incorrect. I'm pretty sure
she was going to multiply the right side of the equation as well, except there is no equation here.

Pick either "gebobs" answer or mine: they are
identical, and correct. By the way, the (x^2+2x-1)
term looks like its easily factorable, but it is not.

Answer 4

No internet site can answer these questions. Perhaps they can teach you how to answer them yourself.

x^2/x+10+9x-10/x+10

We can add the two 10's together

x^2/x +9x-10/x+20


We can cancel x from the first term to get:

x + 9x - 10/x +20

Now we can add the x and the 9x

10x -10/x +20

Factor out the 10:

10(x - 1/x +2)

write the part in parentheses under a common denominator of x:

10((x^2 - 1 + 2x)/x)

we should rearrange the terms in the numerator so they are in order from the highest to lowest power of x:

10((x^2 + 2x - 1))/x))

Answer 5

The very first thing you must learn is to use brackets.
Will assume question is meant to be as follows (but it could be anything the way it has been presented):-
x² / (x + 10) + (9x - 10) / (x + 10)
(x² + 9x - 10) / (x + 10)
(x + 10)(x - 1) / (x + 10)
(x - 1)

PS: Remember brackets!!! You will note, from answers obtained, the confusion you have caused!!!

Answer 6

What you need to do is multiply through by x to get rid of the fractions

x^2 + 10x + 9x^2 -10 +10x

Now add like terms

10x^2 + 20x -10

You can factor this out like this

10(x^2 + 2x -1)

Answer 7

If it is [x^2/(x+10)]+(9x-10)/(x+10) then,

by taking L.C.M,

(x^2+9x-10)/(x+10)

=(x^2+10x-x-10)/(x+10) [factorization]

=[x(x+10)-1(x+10)]/(x+10)

=[(x+10)(x-1)]/(x+10)

=(x-1) [by canceling (x+10)]

Answer 8

research on the internet ther MUST be some website where u find answer 4 math stuff. and good luck! u ned it!!

Answer 9

Ditto!!had none of this when i went to school

Answer 10

sorry, me too.....