Add... 1/(a-b) + 1/b=_______?

Question

Thanks, I need this help for real. Algebra is not my strong point, I am struggling.

Answer 1

First, you need a common denominator. Multiply the first by b/b (which equals 1) and the second by (a-b)/(a-b):

b/[b(a-b)] + (a-b)/[b(a-b)]

Now, add them together:

(b + a - b)/[b(a-b)]

a/[b(a-b)]

a/(ab - b²)

Answer 2

It's exactly the same procedure you used to handle fractions back in elementary school, but with letters instead of numbers. First, find a common denominator:

b/(b(a-b)) + (a-b)/(b(a-b))

Now, add:

a/(b(a-b))

You may want to expand the denominator:

a/(ab-b²)

And we are done.

Answer 3

upload the fractions interior the denominator first, so your denominator is (a + b) / (ab) Now, we are dividing by utilising this FRACTION so we multiply by utilising the reciprocal. answer = (ab) / (a + b)

Answer 4

you have to cross multiply so the answer is:
a2b/ab-b^2