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A glass apparatus contains 2 gases separated by a valve in the middle which contains 2.00 L of H2 on one side, and 1.00 L of N2 on the other side.

Consider the 2.00 L of H2 at a pressure of 415 torr and 1.00 L of N2 at an unknown pressure. If the total pressure in the flasks is 303 torr after the stopcock is opened, determine the initial pressure of N2 in the 1.00 L flask

Thanks!

2007-10-18 02:04:14 · 3 answers · asked by db 3 in Science & Mathematics Chemistry

Can you show the steps in solving this problem please?

A glass apparatus contains 2 gases separated by a valve in the middle which contains 2.00 L of H2 on one side, and 1.00 L of N2 on the other side.

Consider the 2.00 L of H2 at a pressure of 415 torr and 1.00 L of N2 at an unknown pressure. If the total pressure in the flasks is 303 torr after the stopcock is opened, determine the initial pressure of N2 in the 1.00 L flask

Thanks!

2007-10-18 02:26:17 · update #1

3 answers

Once the valve is opened, the pressure of each individual gas is reduced by a factor proportional to the change in the volume.

So, the hydrogen goes from 2 L at 415 tor to 3 L at (2/3)X415=277 torr.

Since the total presure at the end is 303 torr, the presure of both gases is 303 torr, the pressure of N2 at the end is 303-277=25 torr.

Because the initial volume of the N2 was 1/3 of its final volume, the initial pressure of N2 was 3X26=75 torr.

2007-10-18 02:32:32 · answer #1 · answered by hcbiochem 7 · 1 0

somehow I read this question wrong and I thought that 415 was the final pressure. the pressure of nitrogen must be 26 or 27 for the final pressure to be 303.

Thanks!

2007-10-18 02:20:57 · answer #2 · answered by Brent 3 · 0 0

(This answer is inaccurate, please see Dr. A's quite.) V1, P1, T1 = preliminary volume of N2. V2, P2, T2 = very final volume of N2 (on a similar situations because of the fact the H2). we want absolute temperature, so we will convert to ok. P1*V1/T1 = P2*V2/T2 V2 = (P1*V1*T2)/(T1*P2) V2 = (680 mm Hg * 225 mL * 354.7 ok) / (389 ok * 4 hundred. mm Hg) V2 = 349 mL they are reacting in equimolar proportions, so the quantity of H2 needed is a similar. ~~~~~~~~~ playstation Curious Her: Dr. A is nice, I forgot to stability the equation. (Duh.) If it comes all the way down to our 2 solutions, please % Dr. A's answer as ideal? it rather is dazzling; mine isn't. Dr. A: thank you for catching that.

2016-12-29 16:27:21 · answer #3 · answered by ? 4 · 0 0

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