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sq rt ( 5u+10) = sq rt(9u+7)


solve for u


THANKS! =)

2007-10-17 23:42:09 · 8 answers · asked by MTak 2 in Science & Mathematics Mathematics

8 answers

Square both sides, then solve.

sqrt(5u+10) = sqrt(9u+7)
(5u+10) = (9u+7)
5u-9u=7-10
-4u=-3
u=3/4

2007-10-17 23:47:46 · answer #1 · answered by Runa 7 · 0 0

One more solution:
Sq root (5u + 10) = Sq root(9u + 7)
By squaring both side
+/-(5u+10)=+/-(9u+7)
By taking + in LHS and - in RHS
5u+10= -9u-7
=> 14u = -17
=> u= -17/14

2007-10-17 23:58:11 · answer #2 · answered by Anonymous · 0 1

sqrt (5u + 10) = sqrt (9u + 7)

^2 both sides...

5u + 10 = 9u + 7

10 = 4u + 7

3 = 4u

u = 3/4 (Result)

2007-10-17 23:50:18 · answer #3 · answered by Doctor Q 6 · 1 0

_/(5u + 10 = _/(9u + 7)
Square both sides of the equation to remove the radical sign
5u + 10 = 9u + 7
4u = 3
u = 3/4

2007-10-17 23:55:23 · answer #4 · answered by Anonymous · 0 0

if you're square root-ing the whole expression then
sqr rt of 5u+10=sqr rt of 9u+7
(sqr rt of 5u+10)^2=(sqr rt of 9u+7)^2
5u+10=9u+7
10-7=9u-5u
3=4u
u=3/4
just my hunch, haha! XD

2007-10-17 23:50:49 · answer #5 · answered by ylsel1218 1 · 0 0

This last reply is wrong. No +/- here

All the above forgot to check if this value, that is actually right, is really a root of the equation

You have to study the expression's domain or, at least, plug the value in the expression and see if it really is a root

Example

From

x-1 = 2x+1

I get

x = -2

But, from V(x-1) = V(2x+1), if I square, I get this equaion and this root, while V(x-1), when x = -2, doesn't even exist in R

Ilusion

2007-10-18 04:02:17 · answer #6 · answered by Ilusion 4 · 0 0

square both sides to get
5u+10 = 9u+7 then
-4u = -3 and
u = 3/4

Doug

2007-10-17 23:49:32 · answer #7 · answered by doug_donaghue 7 · 1 0

sqrt(5u+10)=sqrt(9u+7)
(5u+10)=(9u+7)
10-7=9u-5u
3=4u
3/4=u or u=.75

2007-10-17 23:54:09 · answer #8 · answered by alecxz 1 · 0 0

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