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why is the calculated values of the resistance (e.g. total resistance) different from the measured values (using a software)? is there any discrepancy between the calculated and measured values?

2007-10-17 22:12:45 · 2 answers · asked by oopsy 1 in Science & Mathematics Physics

2 answers

Yes, it is different due to experimental errors.. calculation will take exact values into account and so u get precise value unlike measured one..

2007-10-17 22:22:14 · answer #1 · answered by Anonymous · 0 0

Calculated values are the theoretically 'perfect' numbers. In the real world, a resistor won't be -exactly- 100 Ω. If it has a gold 4'th band (after the brown-black-brown that says it's 100 Ω) that tells you is a 5% part. And that means its resistance is actually somewhere between 95 Ω and 105 Ω. And it's the same for every element in your circuit. So of course the actual, measured values of voltage, current, etc. will vary slightly from the calculated 'ideal'.

Doug

2007-10-18 06:04:27 · answer #2 · answered by doug_donaghue 7 · 1 0

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