Calculate the heat (calories) produced by the solution of 4.5 g of NaOH. When 4.5g of sodium hydroxide (NaOH) was dissolved in 100g of water and a value of 11.0oC was obtained for ΔT.
2007-10-17 21:40:28 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Assuming you can use the specific heat of liquid water at 14.5 C, which is 4.184 J/g-K, and assuming that the addition of NaOH does not affect the specific heat, then all you need to do is multiply the specific heat by the number of grams of water and by the change in temperature. After which, you convert to calories.
heat = 11.0 K * 100 g * 4.184 J/g-K * (1 cal / 4.184J)
heat = 1100 cal
heat = 1.10 * 10^3 cal
(differences in temperature expressed in Celsius are the same as that in Kelvin)
Oops, it looks like it's easier to use 1 cal/g-K as the specific heat.
2007-10-18 00:37:47 · answer #1 · answered by markedchicken 2 · 0⤊ 0⤋
what are you nuts--I have a thermostat in my house in every room and if it craps the bed I have a big yellow pages book to find a HV systems expert to fix it. If you need a yellow pages directory I'll send you one--free?
2007-10-17 21:46:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Ok Thanks for this one but its abit early in the more for an actual response!
Maybe 2x2 would work better this early!
2007-10-17 21:55:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
That's why I hate chemistry!
2007-10-17 21:44:28 · answer #4 · answered by A Penangite named David® 5 · 0⤊ 0⤋
(11.0)(100) = 1,100 calories
2007-10-17 22:26:13 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋