how can i find it to solve a problem im doing on differentials?
2007-10-17 18:07:29 · 10 answers · asked by sportzblock 1 in Science & Mathematics ➔ Mathematics
f ( x ) = 5 x^(1/2)
f `(x) = ( 5 / 2 ) x ^(-1/2)
f `(x) = 5 / ( 2√x )
2007-10-17 21:35:11 · answer #1 · answered by Como 7 · 0⤊ 0⤋
the answer is 2.5x^(-.5)
that is 2.5 times x to the negative .5th power.
The derivative of x^n where n is any number is found by using this....
nx^(n-1)...I hope this makes sense, but you move the power down, and the new power is n-1...square root of x is the same thing as x to the one half power.
2007-10-17 18:14:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
sqrt x is the same as x^.5.... so drop the .5 and multiply it my the constant, then take the exponent down one... so the finnal derivitive is 2.5x^-.5
2007-10-17 18:10:26 · answer #3 · answered by m m 3 · 0⤊ 0⤋
sqrt(x) = x^0.5
Then the derivative of cx^n = ncx^(n-1)
The same holds true for half powers as integer powers.
2007-10-17 18:09:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5(x)^1/2
5(1/2) x^-1/2
= 5/2x^1/2
2007-10-17 18:12:00 · answer #5 · answered by golffan137 3 · 0⤊ 0⤋
f(x) = 5âx
f'(x) = 5 * (1/2)x^(-1/2) = 5 / (2âx)
2007-10-17 18:11:42 · answer #6 · answered by Madhukar 7 · 0⤊ 0⤋
is the same as 5x^1/2
the derivitive is 2.5x^-1/2
or 2.5/sqrt(x)
2007-10-17 18:10:20 · answer #7 · answered by Aeds 2 · 0⤊ 0⤋
d/dx 5 (sqrt(x)) = 5 d/dx (sqrt(x) = 5 /(2 sqrt(x)).
2007-10-17 18:10:40 · answer #8 · answered by Anonymous · 0⤊ 0⤋
2.5x^-.5
just look at the advice of the guy at the top to work it out
2007-10-17 18:10:50 · answer #9 · answered by Anonymous · 0⤊ 0⤋
y ' = 5 / 2 / sqr(x)
2007-10-17 18:11:47 · answer #10 · answered by CPUcate 6 · 0⤊ 0⤋