if you have fuel that is 20% nitro and you mix and equal amount of 60% nitro solution to it?

Question

what will the concentration of the resulting mixture be. I am mixing 1/2 gal of 20% nitro to 1/2 gal 60% nitro.

Answer 1

1/2 gal * .20 + 1/2gal * .60 = .10 + .30 = .40

1 gallon of 40%

Answer 2

let 20% nitro fuel = x gal

the concentration of nitro fuel in x gal = x*20/100 = 0.20 x

the concentration of 60% x gal nitrofuel = 0.60x

The amount of fuel after addition = 2x gal

let nitro fuel in added fuel = y%

concentration = 2x(y/100)

so 2x y/100 = 0.2x + 0.6x = 0.8x

y/100 = 0.8x/2x = 0.4

y = 0.4 *100 = 40%

When you add equal amounts of two different concentrations, then the resulting concentation would be average of of those two concentrations. In this case (20+60)/2 = 40 %

Answer 3

20% = 1 parts nitro / 4 parts fuel
60% = 3 parts nitro / 2 parts fuel

Complete mixture = 4 parts nitro / 6 parts fuel = 40% nitro / 60% fuel