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How do you find the derivative of the squareroot of x?

2007-10-17 15:03:09 · 3 answers · asked by rainon_me 1 in Science & Mathematics Mathematics

3 answers

sqrt(x) = x^(0.5)

derivative of x^n is just nx^(n-1)

here n =0.5
hence the derivative of sqrt(x) = 0.5x^(0.5-1)
0.5x^(-0.5) or

=1/(2sqrt(x))

2007-10-17 15:07:29 · answer #1 · answered by Anonymous · 1 0

The derivative of a function f(x) = x^r is:

f'(x) = (r-1)x^(r-1)

So for square root, r = 1/2. The derivative would be:

(1/2) * x^(-1/2)

2007-10-17 15:10:20 · answer #2 · answered by Anonymous · 0 0

Easy. Recall that sqrt(x) = x^(1/2).
Now use the power rule to do the derivitive to get
d(sqrt(x))/dx = (1/[2sqrt(x)])

2007-10-17 15:08:22 · answer #3 · answered by cattbarf 7 · 0 0

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