a 1.60 g ice flake is released from the edge of a hemispherical bowl whose radius r is 31.0 cm?

Question

The flake-bowl contact is frictionless.
(a) How much work is done on the flake by its weight during the flake's descent to the bottom of the bowl?
J
(b) What is the change in the potential energy of the flake-Earth system during that descent?
J
(c) If the potential energy is taken to be zero at the bottom of the bowl, what is its value when the flake is released?
J
(d) If, instead, the potential energy is taken to be zero at the release point, what is its value when the flake reaches the bottom of the bowl?
J

Answer 1

A. work = mgh = 0.0016*g*0.31 J.
B. delta PE = -work
C. PE = work
D. PE = -work