2007-10-17 14:36:42 · 5 answers · asked by dbzgt10_ 3 in Science & Mathematics ➔ Mathematics
The powers of i cycle through 1, i, -1, -i
i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1
i^7 = -i
i^8 = 1
If n is even but not divisible by 4, then the value is - 1
and if n is divisible 4 then the value is +1
2007-10-20 09:15:45 · answer #1 · answered by MTvღ..☻..♀..☼..♫ 6 · 0⤊ 0⤋
Ex: i^(n)
If n is even but not divisible by 4, then the value is - 1
and if n is divisible 4 then the value is +1
here n = 752 => 188*4. So 752 is divisible by 4
So the value of i^(752) = 1
2007-10-17 14:45:56 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
The powers of i cycle through 1, i, -1, -i
i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1
i^7 = -i
i^8 = 1
etc.
Since 752/4 = 188 remainder 0
then i^752 = i^0 = 1
2007-10-17 14:41:21 · answer #3 · answered by Marvin 4 · 0⤊ 0⤋
i^4=i^2*i^2=1
so as 752 = 4* 188so i^752 =( i^4)^188 =1
2007-10-17 14:42:00 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
i^752 =
i^(4*188) =
(i^4)^188 =
(1)^188 =
1
2007-10-17 14:40:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋