discontinuity help!!! Plz explain how to get answer!!?

Question

A function f(x) is said to have a removable discontinuity at x=a if:
1. f(x) is either not defined or not continuous at x=a.
2. f(a) could either be defined or redefined so that the new function IS continuous at x=a.
Let f(x) =\frac{2x^2+3 x -5}{x-1}
Show that f(x) has a removable discontinuity at x=1 and determine what value for f(1) would make f(x) continuous at x=1.
Must define f(1)=

Answer 1

f(x) = (2x+5)(x-1)/(x-1) = 2x+5 which is continuos everywhere.
f(1)= 7