A ride that spins like a simple pendulum starts off with such a high amplitude that it swings completely...???

Question

The Jetscream amusement park ride at wonderland is shown here: http://www.pcwjunkies.com/pcw/flatrides/jetscr.htm

It starts off by swinging like a simple pendulum until its amplitude becomes so great that it swings completely around. If the diameter of the circle is 30.0m, what speed must the ship have at the very bottom to just make it to the highest point and sit there with no residual speed?

(use Energy formula- E_k = 1/2mv^2 & E_g=mgh)
..

the mass of the object isnt given though..

Answer 1

Use the law of conservation of energy. At the bottom energy was E_k = 1/2mv^2 because potential energy is 0. At the top energy was E_g = mgh because kinetic energy is 0. So 1/2mv^2 = mgh, so v = sqrt(2gh), where h = 30

Answer 2

authentic, there could be little or no atmospheric friction to sluggish the flow of one in each of those pendulum, however the tug of the moon's gravity, in spite of the indisputable fact that a weaker stress than gravity on the earth or on any greater advantageous physique, could nonetheless be at paintings. One could anticipate the pendulum to return to a supply up finally, all different issues being equivalent.

Answer 3

You have the answer right there.

Solve the equation
1/2mv^2 = mgh
for h.