What is the positive root of the equation x^2=7x+8?

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2007-10-17 12:52:04 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Rewrite it as:
x² - 7x - 8 = 0

Now factor:
(x - 8)(x + 1) = 0

The values of x are:
x = 8 or x = -1

You asked for the positive root so x = 8

2007-10-17 12:57:07 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋

X^2=7x+8
Move everything to one side so your equation is equal to 0
x^2-7x-8= 0
Factor
(x-8)(x+1) = 0
x = 8 or x = -1
therefore the answer is 8

2007-10-17 12:57:51 · answer #2 · answered by Henry Chan 1 · 0⤊ 0⤋