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using the data in the table below and assuming the growth is exponential, when would the populations of Austin and Columbus be equal?

Austin: population: 1990=465,622 2000=656,562
Columbus: population: 1990= 632,910 2000=711,265

2007-10-17 12:46:59 · 1 answers · asked by nathan 2 in Science & Mathematics Mathematics

1 answers

656,562 = 465,622 e^10k
656,562/465,622 = e^10k
ln(656,562/465,622) = 10k
k = 0.1*ln(656,562/465,622) = .034
So for Austin we have P =465,622e^.034t

Similarly for Columbus we have:
P = 632910 e^ .0117t

Populations will be same when:
465622e^.034t = 632910 e^.012t
e^.022t = 632910/465622 = 1.36
t = ln(1.36)/.022 = 14 years
which would be at end of 2004

2007-10-17 13:12:50 · answer #1 · answered by ironduke8159 7 · 0 0

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