addition of rational expression?

Question

simplify
a+4 over 16a + 3a+4 over 4a squared

Answer 1

The common denominator of 16a and 4a^2 is 16a^2 so
multiply top and bottom of first one by a, and top and bottom of second one by 4

a(a+4) + (3a+4)4 on top is a^2 + 4a + 12a + 16 = a^2 + 16a + 16 over the CD of 16a^2

Answer 2

*expressions are written as numerator over denominator, for example

a+4 + 3a+4 ---- is read as a+4 over 16a...get it?
16a 4a2


(a+4)(a) + (4)(3a+4)
16a(a) (4)4a2


a2 + 4a + 12a + 16
16a2 16a2


a2 + 4a + 12a + 16
16a2



a2 + 16a + 16
16a2


(a + 4)2 final answer---(a + 4)squared over 16a squared
16a2

Answer 3

I assume you mean the following...

a + 4 ... 3a + 4
-------- + ---------
.16a ....... 4a²

First you need to find a common denominator.
16 and 4 --> 16
a and a² --> a²

So the common denominator is 16a².

Multiply the first fraction by 'a' (top and bottom):
a² + 4a ... 3a + 4
---------- + ---------
..16a² ....... 4a²

Multiply the second fraction by 4 (top and bottom)
a² + 4a ... 12a + 16
---------- + -------------
..16a² ......... 16a²

Now you have the same denominator so you can add the numerators:

a² + 4a + 12a + 16
--------------------------
........... 16a²

Simplify the numerator:
a² + 16a + 16
-------------------
........16a²

Answer 4

the objective whilst including fractions is to get the comparable denominator. the 1st step in this situation is to element the denominator of the 2d fraction to (x+3)(x-3). Then, to get rid of the x-3 area, multiply the two aspects by x-3. (x-2)(x-3) --------- (x+3) PLUS 10x/(x+3) The numerators can now be blended. First, foil the numerator of the 1st fraction to get x² - 5x + 6 Now, upload the top result with 10x and all of it is going over x+3. x² - 5x + 10x + 6 ------------------------- (x+3) combine like words. x² + 5x + 6 --------------- (x + 3) lastly, element the numerator. (x+3)(x+2) And, the x+3s cancel, leaving x+2 as your very final answer.

Answer 5

18a over 4a squared ..? i could be wrong..