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A 100 gram cue ball traveling at 500 cm/s hits a rack of 15 billiard balls of equal mass. The cue ball is stopped in the collision. Assume all 15 billiard balls move away at the same speed.

A. What is the total momentum before and after the collision?
B. What is the speed of each ball after the collision?

Any help appreciated, I have no clue how to approach this!

2007-10-17 11:18:40 · 2 answers · asked by victoria r 1 in Science & Mathematics Physics

2 answers

let's label the mass of a billiard ball as m
The total momentum is always conserved in a collision

momentum is m*v
.1Kg*5 m/s=.5 kg m/s

since the cue ball stops, all of the momentum gets transferred to the billiard balls so
.5=15*m*v
v=1/(30*m)

j

2007-10-17 12:05:32 · answer #1 · answered by odu83 7 · 0 0

There is many Cue sports including Snooker, Three cushion billiard and Pool. Pool has the most number of variety of games including 9 ball game, Rotation, One Pocket, Straight Pool and so on. There are rules applied on each game but as far as I know 8 ball game is the only Pool game with disputed rule. 8 ball is played in many countries and the rules is varied from each country. In general, the rules goes like this: 1) you must pocket all your balls from your group before pocketing 8 ball. 2) you win the game immediately if you pocket the 8 ball on the break. 3) you lose game when you commit foul during your last shot on 8 ball ( i.e. if you miss the 8 ball, if you scratch and if you hit other ball first. remember: the above three rule are not modified from any country..

2016-05-23 05:36:14 · answer #2 · answered by ? 3 · 0 0

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