The planet Mars has a mass of 6.1 * 10^23 kg and radius of 3.2 * 10^6 m. What is the acceleration of an object in free fall near the surface of Mars? The value of the gravitational constant is 6.67259 * 10^-11 N*m^2/kg^2. Answer in units of m/s^2.
2007-10-17 10:43:08 · 2 answers · asked by josh j 1 in Science & Mathematics ➔ Physics
So get busy and calculate it.
F = G(m_1)(m_2)/r²
It's just plug 'n chug.
Doug
2007-10-17 10:49:47 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
m1 = mass of mars (6.1810^23)
m2 = mass of object (lets say 1kg)
G = 6.67259 * 10^-11
Fg = ?
once you've plugged in all the numbers, you get an answer of
Fg = 4.0687*10^13 N
now...
m = 1kg (just say)
Fg = mg
g = Fg/m
therefore you plug in Fg and get the answer of g = 4.0687*10^13 N/kg
g = a
a = 4.0687*10^13 N/kg or 4.0687*10^13 m/s^2
2007-10-17 10:57:54 · answer #2 · answered by S D 2 · 0⤊ 0⤋