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What is the volume of a mixture of 23.0 g of N2 and 26.5 g of O2 at 47.0°C and 850. mm Hg? Assume the gases do not react with each other.

2007-10-17 09:38:42 · 1 answers · asked by RK 2 in Science & Mathematics Chemistry

1 answers

23.0 g of N2 <==> 0.821 Mol of N2.
26.5 g of O2 <==> 0.828 Mol of O2
Total; 1.649 mol of gas
Use ideal gas law: V = nRT/P = 1.649*0.08206*320.15*(760/850) = 38.7 (L)

2007-10-17 11:41:47 · answer #1 · answered by Hahaha 7 · 0 0

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