Quadratic formula can any one help please?

Question

Solve 6x^2 + 3x – 18 = 0 using the quadratic formula.

Answer 1

Quadratic formula is

x = (-b +/- sqrt(b^2 - 4ac))/2a

for a quadratic equation ax^2 + bx + c = 0.

So in your equation, a = 6, b = 3, and c = -18. Plugging that into the equation, we get

x = (-3 +/- sqrt(3^2 - 4*6*(-18))/2*6
x = (-3 +/- sqrt(9 + 432)) / 12
x = (-3 +/- sqrt(441)) / 12
x = (-3 +/- 21) / 12
x = -24 / 12 or 18 / 12
x = -2 or 3/2.

Answer 2

when the quadratic equation is ax^2 +bx + c = 0

then the formula is x = [-b+/- sqrt(b^2 - 4ac)]/2a

In the given equation 6x^2 + 3x - 18 = 0

a = 6 : b = 3 and c = -18

substituting in the fotmula

x = [-3+/- sqrt(3^2 - 4(6)(-18)]/(2)(6)

= [-3 +/- sqrt(9 + 432)]/12

=[-3+/- sqrt(441)]/12

=[-3 +/- 21]/12

=18/12 or -24/12

x = 3/2 or - 2

Answer 3

Quadratic formula: x = (-b +/- sqrt(b^2 +- 4ac))/2a
Quadratic equation: ax^2 + bx + c = 0.

a = 6, b = 3, and c = -18...just plug and chug at this point...

x = (-3 +/- sqrt(3^2 +- 4(6)(-18))/2(6)
x = (-3 +/- sqrt(9 + 432)) / 12
x = (-3 +/- sqrt(441)) / 12
x = (-3 +/- 21) / 12

When you get to here don't forget its plus OR minus so you must preform both:
x = -24 / 12 OR 18 / 12
x = -2 or 1.5

Answer 4

x = 3/2 and x = -2

Answer 5

quadratic formula is x = (-b +/- Sqrt(b^2 - 4ac)/2a

a = 6, b = 3 and c = -18

b^2 - 4ac = 9 + 4*6*18 = 21

x = (-3 +/- 21 )/12
x = -2 or 1.5

Answer 6

Store values into calculator. Ans. Calculate with minus sign.
6 is A: 3 is B: -18 is C Ans. 54

(-B+square root of (B^2-4AC00/2A and
(-B- - same - but with minus sign

Quadratics have two solutions

Answer 7

x = [-b +/- sqrt(b^2-4ac)]/(2a) where a = 6, b= 3 and c= -18
x = [-3 +/- sqrt(3^2-4(6)(-18)/(2*6)
x = [-3 +/- sqrt(9 + 432)]/12
x = [-3 +/- 21]/12
x = (-3 -21)/12 = -2
x = -3 +21)/12 = 1.5