this is a fraction is the answer -15x^2-30x+4?
2007-10-17 07:03:01 · 7 answers · asked by ann m 1 in Science & Mathematics ➔ Mathematics
no, five is divisable to all terms, so the answe is -3x^2-6x+4
2007-10-17 07:07:30 · answer #1 · answered by m m 3 · 0⤊ 0⤋
(-15x^2-30x+20)/5 Divide 5 through each term
-3x^2 - 6x + 4 ANSWER
2007-10-17 07:07:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
one million: (17x + 8) - (7x + 20) = 17x-7x+8-20 = 10x-12 (A) A. 10x - 12 B. 10x + 28 C. 24x - 12 2: (5x + 9) - (7x + 14) = 5x-7x+9-14 =-2x-5 (B) A. 12x + 23 B. -2x - 5 C. -2x + 23 3: (8x2 + 5x + 15) - (14x2 + 10x + 9) = (8-14)x^2+(5-10)x+(15-9) =-6x^2-5x+6 (B) A. 22x2 + 15x +24 B. -6x2 - 5x + 6 C. -6x2 - 5x + 24 4: (19x2 + 9x + sixteen) - (17x2 + 10x +15) = (19-17)x^2+(9-10)x+sixteen-15 = 2x^2-x+one million (C) A. 2x2 - x - one million B. 2x2 + 19x + 31 C. 2x2 - x + one million 5: (20x4 - 11x + 14) - (7x6 - 19x5 + 10x) = -7x^6-19x^5+20x^4-x+14 (A) A. - 7x6 + 19x5 + 20x4 - 21x + 14 B. - 7x6 - 19x5 + 20x4 - x + 14 C. - 7x6 + 12x5 + 20x4 - 21x + 14 6: (-8x5 - 11x4 - 13x3) - (-20x5 + 17x3 + 6x2)= (-8+20)x^5-11x^4+(-13-17)x^3-6x^2 = 12x^5-11x^4-30x^3-6x^2 (B) A. 12x5 - 11x4 + 4x3 - 5x B. 12x5- 11x4 - 30x3 - 6x2 C. 6x2 + 12x5 - 11x4 + 30x3 7: (-15x2 + 6x - 19) - (-12x2 - 8x - 19) = (-15+12)x^2 +(6+8)x+(-19+19) =-3x^2+14x (B) A. -27x2 + 14x B. -3x2 + 14x C. -27x2 - 2x
2017-01-03 19:44:40 · answer #3 · answered by simonson 3 · 0⤊ 0⤋
-15x^2-30x+20
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5
-3x^2-6x+4
2007-10-17 07:11:36 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
-3x^2 - 6x + 4
2007-10-17 07:06:07 · answer #5 · answered by papastolte 6 · 0⤊ 0⤋
izit bruv
2007-10-17 07:05:18 · answer #6 · answered by jack h 1 · 0⤊ 0⤋
I think the answer is 35!!!!!!!!!!!!!!!!!!!!!
2007-10-17 07:12:45 · answer #7 · answered by Twilighter 2 · 0⤊ 0⤋