does anyone know the answer to this?
2007-10-17 05:56:00 · 4 answers · asked by Theo d 1 in Science & Mathematics ➔ Mathematics
f(x) = 3sin (2x)
f'(x) = 6cos (2x)
f'(0) = 6cos (2*0)
f'(0) = 6*1
f'(0) = 6
2007-10-17 05:59:52 · answer #1 · answered by Lucky 4 · 0⤊ 0⤋
Calculating f'(0) means that you are taking the derivative of f(x) and then plugging in 0 for x. So we have:
f'(x) = 6cos(2x) because the derivative of sin(a number) is cos(a number), but the chain rule states that you have to multiply the front of the expression by the coefficient inside the parentheses. Therefore, you are multiplying 3 * 2, which is why the 6 is in front of the cos(2x).
Now plug in 0 for x. You get
6cos(2*0) = 6cos(0)
The cos(0) = 1.
Therefore, you have 6 for your answer.
2007-10-17 06:03:36 · answer #2 · answered by 3545 2 · 0⤊ 0⤋
f'(x) = 6 cos 2x
so
f'(0) = 6.
2007-10-17 06:02:23 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
f'(x)=6sin(2x)
f'(0)=6cos(0) =6
2007-10-17 06:00:06 · answer #4 · answered by chasrmck 6 · 0⤊ 0⤋