2007-10-17 04:07:57 · 5 answers · asked by princes3242000 1 in Science & Mathematics ➔ Physics
A larger frequency means there is a smaller wavelength and a smaller frequency means there is a larger wavelength ie. they are inversely proportional.
2007-10-17 04:13:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
In order to undersatnd fundamental concepts one has to take the simplest example that of a pure one dimensional wave motion along a straight line. Such a motion has three features. First perodicity of space. Second periodicity of time and third the whatever is the condition at a point the same condition travels to other point with a fixed velocity. If you look at the whole line at the same time you find that after some minimum distance the condtion is the same. By condition I mean the displacement from mean position and velocity, together this is known as phase. This minimum distance which you may call space period is in fact wavelength, 'lambda'. Now if you concentrate your attention on any one point on the line. You would find the condition repeats after some minimum time, T. That happens to be the time period. Because both these periodicities are to be mantained throughout all time and space. The disturbance at any point must travel through a distance one wavelength in time interval of one period. So velocity has to be "lambda/T"
or "lambdaxf", where f is 1/T.
2007-10-17 05:08:29 · answer #2 · answered by Let'slearntothink 7 · 0⤊ 0⤋
Wavelength λ is inverse proportional with the frequency ν (Greek "nu"), the number of wave periods per time unit passing a given point.
We use the equasion: λ = vw/v ,where vw is expressed in 'metres per second'.
e.g. For sound waves in air, the speed of sound: 344 m/s. If we then input the given frequency we can calculate the wavelength.
2007-10-17 04:16:26 · answer #3 · answered by stilgar91 2 · 0⤊ 0⤋
velocity/wavelength=frequency frequency/velocity=wavelength in case you have the two the wavelength or the frequency you will locate out the different variables. while you're conversing approximately electromagnetic waves, velocity is persevering with, it relatively is 2.99x10^8 m/s, so which you will continuously be searching for wavelength or frequency.
2016-12-18 09:56:11 · answer #4 · answered by ? 4 · 0⤊ 0⤋
inversely
2007-10-17 05:54:17 · answer #5 · answered by mojorisin 3 · 0⤊ 0⤋