Another circular motion question?

Question

To appreciate the forces that a fighter pilot must endure, consider the magnitude of Fn of the normal force that the pilot's seat exerts on him at the bottom of a dive. The magnitude of a pilot's weight is W. The plane is travelling at 230 m/s on a vertial circle of radius 690 m. Determine the ratio Fn/W.

Answer 1

Fn/W (the g's acceleration she feels) = 1+(v^2/r)/g = 8.823 g's.
Note that gravity and centripetal force are in the same direction, head-up or head-down. (Head-down at the pullout? That's news to me. I guess they don't need g-suits any more.)

Answer 2

The vertical forces acting on the pilot are W acting downward and Fn acting upward. The difference between the two must provide the centripetal force required. That is
Fn - W = (m*v^2)/r.
This gives
Fn/W = 1+(m*v^2)/r*W
= 1+v^2 / r*g
Taking g as 10 m/s^2 approx, this works out to 8.7

Answer 3

At the bottom of the dive, pilot's position is head down. In this position, the resultant of Fn and W(= mg, downwards) must be upwards and equal to centripetal force mv^2 / r. For this Fn has to be upwards and seat provides this force through the waistband.
Fn - W = mv^2 / r
=> Fn / W - 1 = (mv^2 / r) / mg ( W = mg)
=> Fn / W
= v^2 / rg
= (230)^2 / 690*9.8
= 7.82.

Answer 4

(a) geometry of a circle => C = 2?R {R = 0.2 hundred m} U can calculate this :>) (b) for tip velocity: first calculate w = angular velocity in rad/s = (1110 rpm) x (2?/60) = ________ rad/s then multiply w via R to locate tip velocity = V =________ m/s (c) T = era = ans (a) / ans (b) = C/V