how do i do that?
2007-10-17 03:25:03 · 14 answers · asked by miri_321 1 in Science & Mathematics ➔ Mathematics
(6x-4)-(3x-5)=22
Apply the negative sign through the second term:
6x -4 - 3x + 5 = 22
Combine like terms:
6x - 3x + 5 - 4 = 22
3x + 1 = 22
Isolate the constants on one side, and x terms on the other:
3x = 21
Divide each side by 3:
x = 21/3 = 7
2007-10-17 03:28:20 · answer #1 · answered by MamaMia © 7 · 3⤊ 1⤋
6x - 4 - 3x + 5 = 22
6x -3x -4 +5 = 22
3x + 1 = 22
3x = 22 - 1
3x = 21
x = 21/3
x = 7 ~ final answer
2007-10-17 03:45:16 · answer #2 · answered by Angelina 2 · 0⤊ 1⤋
Simple.
6x - 3x -4 + 5 = 22
3x + 1 = 22
3x = 21
3x = 7
2007-10-17 03:29:30 · answer #3 · answered by simpsons_simp 2 · 1⤊ 1⤋
(6x-4) - (3x-5) = 22
6x - 4 - 3x + 5 = 22 (Multiply the negative sign to 3x and - 5)
6x - 3x +5 -4 = 22 ( We rearrage it to make it clear for you)
3x +1 = 22
3x = 22 -1 (transpose the 1 to the other side and change the sign from positive to negative)
(3x = 21) /3 (we divide both sides by 3 because you only need the x value)
x = 21/3 or x = 7 (your final answer)
2007-10-17 04:33:35 · answer #4 · answered by lon_joe 2 · 0⤊ 1⤋
Distribute the negative by the () =
6x - 4 -3x + 5 = 22
Combine like terms=(add the ones that look alike)
3x+1=22
Subtract the 1 from each side.
3x=21
Divide the three by eac side.
x=7
2007-10-17 03:32:52 · answer #5 · answered by Anonymous · 1⤊ 1⤋
(6x-4)-(3x-5)=22
6x - 4 - 3x + 5 = 22
Combine similar terms:
3x + 1 = 22
Subtract 1 to both sides of the equation:
3x = 21
Divide both sides of the equation by 3:
x = 7
2007-10-17 04:14:07 · answer #6 · answered by edith p 3 · 0⤊ 1⤋
6x - 4 -3x + 5 = 22
3x + 1 = 22
3x = 21
x = 7
2007-10-17 03:29:27 · answer #7 · answered by Art B 1 · 1⤊ 1⤋
3x - 4 + 5 = 22
3x = 21
x = 7
2007-10-17 03:44:14 · answer #8 · answered by Como 7 · 0⤊ 1⤋
6x-4-3x+5=22
3x+1=22
3x=21
x=21/3
x=7
2007-10-17 03:39:13 · answer #9 · answered by anma_cy 3 · 0⤊ 1⤋
(6x - 4) - (3x - 5) = 22
6x - 4 - 3x + 5 = 2 2
3x + 1 =22
3x = 21
x=7 (Ans)
2007-10-17 03:30:00 · answer #10 · answered by Anonymous · 1⤊ 1⤋