Differentiate the following function. y=5e^x+2...
i thought it would be e^x since the 2 becomes zero and the five i thought went away but thats not right.
2007-10-17 02:54:47 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If you mean 5e^(x+2),
y' = (5)e^(x+2)
You can see this by substituting u = x+2
y = 5e^u
y' = 5e^u du = 5e^u = 5e^(x+2)
If you mean (5e^x) + 2,
y' = 5e^x
2007-10-17 02:59:45 · answer #1 · answered by MamaMia © 7 · 1⤊ 1⤋
differential of Constant X F(x) = Constant X Differential of F(x)
so the answer is 5e^x
2007-10-17 03:01:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
dy/dx = 5e^x
2007-10-17 03:42:48 · answer #3 · answered by Como 7 · 0⤊ 0⤋
dy/dx = 5e^x
2007-10-17 03:00:27 · answer #4 · answered by analog 2 · 0⤊ 0⤋
dy/dx = 5e^x
2007-10-17 02:58:57 · answer #5 · answered by fcb 1 · 0⤊ 0⤋
y=5e^x
2007-10-17 03:44:22 · answer #6 · answered by XxSyNd3rXx 2 · 0⤊ 0⤋
well the derivative of cos( u ) = - sin (u) * (the derivative of u) In other words... [ - sin (something)] TIMES THE DERIVATIVE OF THAT "SOMETHING" f(x) = cos(x^2 + 4x) so... f '(x) = - sin (x^2 + 4x) * (x^2 + 4x)' f '(x) = - sin (x^2 + 4x) (2x + 4) You can leave the answer like that or put the (2x + 4) in the front. It doesn't matter.
2016-05-23 03:41:30 · answer #7 · answered by ? 3 · 0⤊ 0⤋
differential of e^x is always e^x
differential of ke^x is always ke^x , where k is constant
differential of ke^x + C is also ke^x
2007-10-17 03:02:26 · answer #8 · answered by mohanrao d 7 · 0⤊ 0⤋
5e^x
2007-10-17 02:57:47 · answer #9 · answered by vasu 1 · 0⤊ 3⤋