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i need help factoring.

2007-10-16 18:02:18 · 8 answers · asked by Desiree S 1 in Science & Mathematics Mathematics

thank you for your help everyone.

2007-10-16 18:17:08 · update #1

8 answers

6x² + 11xy +4y² =
multiply 6(4) = 24
look for factors of 24 that add up to 11: 8 and 3

6x² + 3xy + 8xy + 4y² =
3x(2x + y) + 4y(2x + y) =
(3x + 4y)(2x + y)

2007-10-16 18:06:38 · answer #1 · answered by Philo 7 · 1 0

6x(squared)+11xy+4y(squared)=(3x+4y)(2x+1y)
If you use the FOIL formula to check my answer you can see that is the correct one F extends for first. O for outters. I for inners and L for last.first 3x times 2x = 6x(squared then outters 3x times 1y = 3xy then inners 4y times 2x = 8xy and finally last 4y times 1y = 4y(squared). Then you have 6x(squared) and add 3xy + 8xy and you get 11xy and last you have 4y(squared). i hope this answer helps you lep me know

2007-10-16 18:18:09 · answer #2 · answered by pockemon 1 · 0 0

6x^2+11xy+4y*2=0

(3x+4y)(2x+y)=0

3x+4y=0
x1=-3/4y x2=-1/2y

2007-10-16 18:24:23 · answer #3 · answered by Faisal R 3 · 0 0

while you're in Australia, type in the 1st 4 digits of your telephone selection at step a million. Then it works. it truly is an easy calculation made complicated: X - first a million/2 of your telephone selection Y - 2nd a million/2 of your telephone selection X*(eighty+a million)*250=X*20250 X*20250+2*Y=2*(X*10,000+Y)+250 now subtract 250 and divide by skill of two leaves you with X*10,000+Y it is your telephone selection To get the 1st a million/2 of your telephone selection to 'meet up' with the 2nd section you may desire to multiply it by skill of 10,000 (shift it 4 decimal places to the left). sensible although...

2016-10-12 22:12:44 · answer #4 · answered by ? 4 · 0 0

(3x+4y)(2x+y) im to lazy to check but im sure thats right.

2007-10-16 18:08:07 · answer #5 · answered by trunks610 2 · 0 1

(3x+4y)(2x+y)

2007-10-16 18:14:32 · answer #6 · answered by Natali 2 · 0 1

(3x+4y)(2x+y)

2007-10-16 18:11:35 · answer #7 · answered by Anonymous · 0 1

(3x + 4y)(2x + y)

:]

2007-10-16 18:09:35 · answer #8 · answered by hellosunshine 3 · 0 1

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