Does anyone know the answer?

Question

If a rock is thrown upward with an initial velocity of 32 feet per second from the top of a 40-foot building what is the height in equation form

Answer 1

h = 40 + 32t - 16t²

Answer 2

this is physics somehow, and is a free fall problem.

Vf^2 = Vi^2 + 2as
where in this problem, a is the same with G which is -10 (or 9.8 depends on your class standard)

and s is from the highest point from the top of the buiding.

Vf, however, is 0, because once the object reaches its peak, it stops (for like less than 1 sec, lol)

so.

0 = 32^2 - 2*10*S

S= 51.2

51.2+40 = 91.2 ft

Answer 3

h = 40 + 32t - 16t²

Answer 4

h=vt - 16t^2 (when you're dealing with feet).

then plug all the stuff in.
i learned this just today.