What's the derivative of cos(squared) theta and 1+cos2theta?

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2007-10-16 16:38:33 · 3 answers · asked by Heell yeaah! 3 in Science & Mathematics ➔ Mathematics

Derivative of cos^2 is 2cos theta times(-sin theta) which is equivalent to -2cos x sin x.
Derivative of (1+cos 2x) =0+ (-sin 2x)(2)=-2sin 2x.

2007-10-16 18:10:09 · answer #1 · answered by mlam18 6 · 0⤊ 0⤋

Cos Squared

2016-10-21 03:54:12 · answer #2 · answered by endo 4 · 0⤊ 0⤋

y = ( cos θ ) ²
dy/dθ = 2 ( cos θ )( - sin θ )
dy/dθ = - sin 2θ

y = 1 + cos 2 θ
dy/dθ = ( - sin 2 θ )( 2 )
dy/dθ = - 2 sin 2 θ

2007-10-16 20:02:43 · answer #3 · answered by Como 7 · 1⤊ 0⤋