2007-10-16 15:34:59 · 10 answers · asked by JulieG 1 in Science & Mathematics ➔ Mathematics
(y - 7)(y - 6) = 0
y = 6 , y = 7
2007-10-18 07:31:28 · answer #1 · answered by Como 7 · 0⤊ 0⤋
y = 6 or y = 7
2007-10-16 15:37:46 · answer #2 · answered by j 2 · 0⤊ 0⤋
That is actually a pretty easy quadratic because it factors nicely into (y-7)(y-6)=0 (-7-6=-13 and (-7)(-6)=42)
Now set each one equal to zero
y-7=0 so y=7
y-6=0 so y=6
2007-10-16 15:42:44 · answer #3 · answered by cgflann 4 · 0⤊ 0⤋
OK
y^ 2 - 13 y + 42 = 0 ; factorize
(y -6)(y-7) = 0
y = 6 or y= 7
Hope this helps.
2007-10-16 15:38:09 · answer #4 · answered by pyz01 7 · 1⤊ 0⤋
usually its in the form X^2 - 13x +42 = 0
but in this the roots are 6 and 7.
2007-10-16 15:38:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y^2-13y+42=0
(y-6)(y-7)=o
y=6 or 7
2007-10-16 15:43:13 · answer #6 · answered by u chi 2 · 0⤊ 0⤋
Use the quadratic equation, -b +/- the square root of b^2 - 4ac all divided by 2a.
2007-10-16 15:37:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
(y - 6) (y - 7) = 0
y=6 or y=7
2007-10-16 15:44:05 · answer #8 · answered by ? 4 · 0⤊ 0⤋
(y-7)(y-6) = 0
y = 7
y=6
2007-10-16 15:38:21 · answer #9 · answered by nats.. 3 · 0⤊ 0⤋
34
j.k
thats freakin hard....
2007-10-16 15:37:25 · answer #10 · answered by mexicanguy_2890 2 · 0⤊ 0⤋