2007-10-16 15:14:51 · 4 answers · asked by JulieG 1 in Science & Mathematics ➔ Mathematics
Problem shoud read: 2x^2 - 35 + 15
2007-10-16 15:16:06 · update #1
2x^2-35=15 add 35 on both sides
2x^2-35 +35=15+35
2x^2=50 devided by 2 on both sides
2x^2/2=50/2
x^2=25 take square root of both sides
x= 5, or -5
2007-10-16 15:19:29 · answer #1 · answered by Allen C 3 · 0⤊ 0⤋
It probably should read:
2*x**2 - 35 = 15 or x**2 = 50/2=25 or x = 5
2007-10-16 15:23:29 · answer #2 · answered by LucaPacioli1492 7 · 0⤊ 0⤋
2x2 – 35 = 15
Transpose - 35 to the other side of the equation:
2x2 = 35 + 15
2x2 = 50
Divide both sides of the equation by 2
x2 = 25
Find the square root of both sides of the equation:
x = 5
2007-10-16 15:26:18 · answer #3 · answered by edith p 3 · 0⤊ 0⤋
2x^2 - 35 = 15
2x^2 = 50
x^2 = 25
x = +/- 5
2007-10-16 15:19:53 · answer #4 · answered by minako485 2 · 0⤊ 0⤋