A mixture of gases collected over water at 14 celsius has a total pressure of 0.981 atm and occupies 55 mL
how many grams of water escaped into the vapor state?
what volume does the mixture of gases, exclusive of the water vapor, occupy?
what volume does the mixture of gases, exclusive of the water vapor, occupy at STP conditions
2007-10-16 14:52:04 · 1 answers · asked by maybe71400 1 in Science & Mathematics ➔ Chemistry
Saturated water vapor pressusre at 14C: 0.01577 atm
Thus the partial pressure of other gases: 0.965 atm.
how many grams of water escaped into the vapor state?
PV/RT = 0.016*0.055/(0.08206*287.16) = 3.73x10^-5 (mol)
3.73x10^-5 (mol)*18g/mol = 0.00067g
what volume does the mixture of gases, exclusive of the water vapor, occupy?
55 mL
what volume does the mixture of gases, exclusive of the water vapor, occupy at STP conditions?
PV/T = pv/t
v = PVt/pT = 0.965*0.055*273.15/(1.00*287.16)
= 0.050 L = 50mL
2007-10-18 12:06:06 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋