Can someone help me do this chemistry problem?

Question

Mix 200 grams of 90 degree celsius tea with 10 grams of 0 degree ice. find final temperature at equilibrium.

Answer 1

The heat of fusion of water: 79.72 cal/g.
The heat capacity of water: 1.000 cal/g·ºC.
Let the final temperature at equilibrium to be TºC.
10*(79.72 + 1.000*T) = 200*1.000*(90 - T)
Solve for T and you get the answer!