5x is over x-x2 (the 2 is an exponent)
2007-10-16 13:23:11 · 8 answers · asked by R.K.O.L 2 in Science & Mathematics ➔ Mathematics
(-5x) / (x)(x - 1)
- 5 / (x - 1)
2007-10-17 22:36:17 · answer #1 · answered by Como 7 · 0⤊ 0⤋
5x/(x-x^2)=5x/x(1-x)=(5x/x(1-x)) times (1-x)= 5x/x=5
factor out an x from the (x-x2) to get x(1-x). then multiply top and bottom by (1-x); and it cancles out. u r left with 5x/x. divide out the x to get 5.
2007-10-16 20:35:16 · answer #2 · answered by ohiopinktiger 2 · 0⤊ 0⤋
Factor an x out of your denominator:
(-5x)/x(1-x)
-5/(1-x)
Think that's about as simple as it gets.
2007-10-16 20:26:04 · answer #3 · answered by Tim P. 5 · 0⤊ 0⤋
Divde the top and bottom of -5x / (x - x^2) by x to get -5 / (1 - x). That's about as simple as you can get it.
2007-10-16 20:26:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-5x/x(1-x) = 5/(x-1)
2007-10-16 20:26:54 · answer #5 · answered by John V 6 · 0⤊ 0⤋
5x
2007-10-16 20:30:05 · answer #6 · answered by Anonymous · 0⤊ 0⤋
-5x
____
x - x^2
-5x
______
x(1-x)
5
______
(x-1)
Answer
2007-10-16 20:37:13 · answer #7 · answered by Anonymous · 0⤊ 0⤋
5x
----
x-x^2
5x
----
x^3
2007-10-16 20:26:32 · answer #8 · answered by i_heart_kasey_kahne9 3 · 0⤊ 1⤋