Can anyone explain how to solve equations with variables on both sides?

Question

explain to me how to solve equations with variable on both sides. heres mi problem: 6(f+5) = 2f - 8

Answer 1

6f + 30 = 2f - 8
4f + 30 = - 8
4f = - 38
f = - 38 / 4
f = - 19 / 2

Answer 2

It's easy to rewrite this equation so that the variables are on only one side. If you subtract (2f - 8) from both sides you get 6(f+5) - (2f - 8) = 0. Now you can solve it the usual way.

Answer 3

6(f+5) = 2f - 8

First distribute the 6 through the parentheses:
6f + 30 = 2f - 8

Now subtract 2f from both sides (to get it only on the left):
4f + 30 = -8

Now subtract 30 from both sides (to get numbers on the other side):
4f = -38

Finally divide both sides by 4:
f = -38/4
f = -19/2
f = -9½

Answer 4

distribute the 6 first, so it would be 6f+30=2f-8, and then you would want to get the number and the variables on different sides, so you would minus them, so it would be 4f=-38, which equals f=-9.5

Answer 5

Q1: 7x = x - 54 6x = - 54 x = - 9 Q2: - 8x - x = 24 - x 8x = - 24 x = - 3 Q3: 2(3 - 4x) = 4 + 4(6 - x) 3 - 4x = 2 + 2(6 - x) 3 - 4x = 2 + 12 - 2x 2x = - 11 x = - 11/2 Q4: 9(2x + 3) = - 36 - 27(x + 2) 2x + 3 = - 4 - 3(x + 2) 2x + 3 = - 4 - 3x - 6 5x = - 13 x = - 13/5

Answer 6

6(f + 5) = 2f - 8
6f + 30 = 2f - 8

combine terms

6f - 2f = -8 - 30

now solve
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Ms. Exxclusive : you cheat, you are not suppose to write hold on, submit it so you get to be first then go back and edit it,

Answer 7

Yes indeed. This is just what I studied in algebra so many years ago. And I fish it out of my mind:

6(f+5)=2f-8
6f + 30 = 2f -8
-2f -2f
--------------------
4f + 30 = -8
-30 -30
--------------------
4f = -38
4f/2 -38/2
--------------------
f = -19

WOW!

Answer 8

move the variables to one side then solve it

Answer 9

f= -9