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Calculate the specific heat of a metal. in J/kg.K, from the following data. A container made of the metal has a mass of 3.6 kg and contains 15.0 kg of water, a 1.8 kg of The metal initially at temperature of 187.0°C is dropped into the water. the container and the water have a initial temperature of 16.0°C and the final temperature of the entire system is 18.0°C.

2007-10-16 13:05:44 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

if you consider the drop in heat in the metal as raising the heat in the water and container, then
the metal gives up
1.8kg x 169 deg (change) x specific heat
equals the increase in water
15 x 2 x 1 (spec heat of water)
plus the container
3.6 x 2 x spec heat
so
1.8 x 169 x S = 15 x 2 + 3.6 x 2 x S.

solve for S

2007-10-16 13:37:47 · answer #1 · answered by Piglet O 6 · 0 0

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