show work for best answer
2007-10-16 12:40:19 · 5 answers · asked by skinzfan36 1 in Science & Mathematics ➔ Mathematics
1st answer what are you even talking about?
2007-10-16 12:45:51 · update #1
accoring to the definition of derivative f-prime(x)=lim as t approaches x
(the answer will involve the variables t and x)........can one of you get this part too, whoever does gets best answer, thanks
2007-10-16 12:54:47 · update #2
No...I didn't lose it , so YOU find it....
2007-10-16 12:44:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
f(x)= 3/x^2 -sqrt(7)
f'(x)=3x^-2 -sqrt 7
= -6x^-3
= -6/x^3 <-- derivitive using Dy/Dx
2007-10-16 12:49:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋
f(x) = (3/x^2)-sqrt(7)
3/x^2 =3x^(-2)
f'(x)=(3)(-2)x^(-3)=-6/x^3-zero
derivative of a constant is 0.
f'(x)=-6/x^3
2007-10-16 12:49:50 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋
f(x) = 3/x^2 - sqrt(7)
= > 3x^(-2) - sqrt(7)
f'(x) = -6 x^(-2-1) -0 = -6x^(-3)
f'(x) = -6/x^3
2007-10-16 12:49:45 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋
f(x)=(3/x^2)-sqrt(7)
dy/dx = [x^2(0) -3(2x)]/x^4 + 0
dy/dx = -6x /x^4 = -6/x^3
2007-10-16 12:51:10 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋