If the angles of a triangle are represented by x, (3x+20, and 6x, the triangle must be...
a) isosceles
b)right
c) obtuse
d) acute
please explain
thanks
2007-10-16 12:40:18 · 7 answers · asked by Magnun S 3 in Science & Mathematics ➔ Mathematics
The sum of the angles in a triangle must add to 180, so add these up and solve for x then plug back in to get the actual angles.
x + (3x + 20) + 6x = 180
10x + 20 = 180
10x = 160
x = 16
The angles are 16°, 68° and 96°
The largest angle is greater than 90° and no angles have the same value so the answer is the triangle must be:
c) obtuse.
2007-10-16 12:42:59 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
since the total angle of a triangle is 180 you come up with the equation 180=10x+20 then you subtract 20 from each side trying to get only x on a side, then you have the equation
160=10x, next you divide both sides by 10 so you have a single "x" on one side, then you get the answer x=16.
2007-10-16 19:53:17 · answer #2 · answered by Special k 2 · 0⤊ 0⤋
x + (3x + 20) + 6x = 180
10x = 160
x = 16
3x + 20 = 68
6x = 96
one angle greater than 90°, so obtuse
2007-10-16 19:45:09 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
all the angles will add to 180, so:
x+3x+20+6x=180
10x+20=180
......-20.....-20
10x=160
/10...../10
x=16
so the 3 angles are 16, 68, and 96
96 is above 90 so it is obtuse
hope i helped =]
2007-10-16 19:47:06 · answer #4 · answered by Mariee 4 · 0⤊ 0⤋
x + 3x + 20 + 6x = 180
or 10 x = 150
or x = 15
The angles are 15, 65, 90
the answer is (b) - right angle traingle
2007-10-16 19:44:49 · answer #5 · answered by ib 4 · 0⤊ 1⤋
x+3x+20+6x=180...
anywhoo, I would say that'd be a right triangle, becasue none of the angles are congruent...
2007-10-16 19:44:47 · answer #6 · answered by Anonymous · 0⤊ 1⤋
x+(3x+20)+6x=180
x=16
angels are 16,96,68
obtuse
2007-10-16 19:48:53 · answer #7 · answered by john 4 · 0⤊ 0⤋