Help me do this equation and give me all the steps please!!
2007-10-16 12:38:40 · 6 answers · asked by Joeseph 2 in Science & Mathematics ➔ Mathematics
2^(x-1)=64
2^(x -1) = 2^6
or (x -1) = 6
or x =7
2007-10-16 12:42:01 · answer #1 · answered by ib 4 · 0⤊ 0⤋
Looks like homework to me. Unfortunately, asking someone to do your homework doesn't seem to be a violation of community standards.
In any case, you can solve the problem as follows:
2^(x-1) = 64
x-1 = 6
x = 7
2007-10-16 19:41:43 · answer #2 · answered by Arthur R 5 · 0⤊ 0⤋
Take the ln of each side
so (x-1)ln 2 = ln 64
x-1 = 6
x=7
2007-10-16 19:42:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x-1 log 2 = log 64
x-1 = log64/log 2
x -1 = 6
x = 7
2007-10-16 20:05:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
64 is 2^6, so
2^(x-1) = 2^6
x-1 = 6
x = 7
2007-10-16 19:42:29 · answer #5 · answered by Philo 7 · 0⤊ 0⤋
(x-1)log2 = log 46
x - 1 = log 46/log 2
x = log 46/2 + 1
I hope that this is correct.
2007-10-16 19:42:14 · answer #6 · answered by Steve B 6 · 0⤊ 0⤋