2007-10-16 12:08:35 · 15 answers · asked by kodakboi 1 in Science & Mathematics ➔ Mathematics
2x+7=5x+16
7-16=5x-2x
-9=3x
-3=x
x=-3
2007-10-16 12:12:53 · answer #1 · answered by "vanpersie" 2 · 0⤊ 1⤋
2x + 7 = 5x + 16
2x - 5x = 16 - 7
-3x = 9
x = 9/ -3
x = -3
2007-10-16 12:17:39 · answer #2 · answered by kitten 4 · 0⤊ 0⤋
2x + 7 = 5x + 16, so
-9 = 3x, so
x = -3.
2007-10-16 12:13:12 · answer #3 · answered by Twiggy 7 · 0⤊ 1⤋
-7 both on left side
2x=5x+9
-5x on right side
-3x=9
x=-3
2007-10-16 12:16:33 · answer #4 · answered by CoolioMADDog 4 · 0⤊ 0⤋
2x+7=5x+16
Ok. First you subtract 2x from both sides.
7=3x+16
Then you subtract 16 from both sides to get x by itself.
-9=3x
Divide both sides by 3x to get x by itself.
x=-3
2007-10-16 12:14:09 · answer #5 · answered by b 5 · 0⤊ 1⤋
2x+7-16=5x+16-16
2x-9=5x
2x-2x-9=5x-2x
-9=3x
-3=x
2007-10-16 12:20:21 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
x = -3
2007-10-16 12:13:35 · answer #7 · answered by Cuefrogger 2 · 0⤊ 1⤋
What about it?
If the question is "Could somebody solve the equation for me, for free?" then just subtract 5x from both sides, subtract 7 from both sides, and divide both sides by -3.
2007-10-16 12:12:09 · answer #8 · answered by Anonymous · 1⤊ 1⤋
Subtract 2x from both sides
7 = 3x +16
Subtract 16 from both sides
-9 = 3x
Divide both sides by 3
x = - 3
FOR THE RECORD JESLYN ... we could have all been solving at the same time and not seen the other posts. Or, we can show more than one way to solve ... OR frequent answers could reinforce the correct answer ...
2007-10-16 12:13:01 · answer #9 · answered by Kelley Sue 2 · 0⤊ 2⤋
log(4)(sixty 4^(-2x + 7) * 16^(5x - 7)) log(4)((4^3)^(-2x + 7) * (4^2)^(5x - 7)) log(4)(4^(3(-2x + 7)) * 4^(2(5x - 7))) log(4)(4^(-6x + 21) * 4^(10x - 14)) log(4)(4^((-6x + 21) + (10x - 14))) log(4)(4^(-6x + 21 + 10x - 14)) log(4)(4^(4x + 7)) (4x + 7) * log(4)(4) (4x + 7) * (log(4)/log(4)) (4x + 7) * a million ANS : 4x + 7
2016-10-21 06:58:26 · answer #10 · answered by buncie 4 · 0⤊ 0⤋