1. s=2g
2. 25+8.5s
3. 1/2d
4. (n+10)/ 24
5. 45h
2007-10-16 11:28:52
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answer #1
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answered by rk <3 :D 3
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Algebra is a process of expression using symbols instead of words. First identify a phrase that establishes a constant. In #1 it is "last year's group." Let that equal "x." The statement is saying that the number you are looking for [The number of students interested -- call it "y"] is twice your constant. "y" is 2 times "x," or 2x. Therefore, y = 2x.
#2 Our constant is $25 + ($8.50 times the number of hours on court.) Let y = the total cost, and x = the number of hours on court. Therefore, y = $25 + $8.50x.
#3 y = distance to the match; x = total distance traveled. y = x/2.
#4 The number we want to know is x. The sum of x + 10 = 24. To isolate x, subtract 10 from each side of the equation. x + 10 - 10 = 24 - 10; x = 14. To check, substitute the value of x back into the equation.
#5 Let y = total miles traveled; let x = the number of hours traveled. Therefore, y = 45x. [x could be a fraction of an hour, too.]
Here's your question. You have two coins that add up to 30 cents and one of them isn't a nickel. What two coins do you have?
2007-10-16 11:42:05
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answer #2
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answered by William M 1
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1. Last year's group = X. So this year's group is twice as big or 2X. (You could also express this year's group as X and call last year's group 1/2X --- I don't like working with fractions if I can avoid them)
2. Hour on court = X. Cost of playing tennis is 8.5X plus $25
3. Distance to match = X. Traveling half the distance could be shown as .5X or X/2
4. A number = X. (X+10)/24
5. Hour = X. 45X will give you the total miles traveled.
The trick to these problems is finding your variable. I used X to represent the variable in each one. There are different ways to express each of these so you may see some variations in the answers listed. Try to figure out which value you don't know in the problem----for example, in #2, the only thing that will change is the number of hours. The cost per hour and the membership fee are set.
2007-10-16 11:31:54
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answer #3
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answered by TaxGurl 6
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1. 2x=y where x is the number of students last year and y is the number of students this year
2. 25+8.5x=y where x is the number of hours they played and y is the total they played
3. 1/2x=y where x is the distance traveled last time and y is the distance traveled this time
4. (x+10)/24=y Don't forget the parenthesis because you need to add x=10 before you divide by 24
5. well you need to say how long he was traveling for unless this is it: 45/60x=y where 45 is how fast you are going divided by the number of minutes in an hour and y is the total distance traveled.
2007-10-16 11:33:54
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answer #4
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answered by Anonymous
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2n (where n is the number of last year's group)
8.50x + 25 (where x = the number of hours you used the court)
1/2n (where n = the distance to the match)
(x + 10)/24
(45/60)*n (where n = the number of minutes travelled)
2007-10-16 11:33:14
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answer #5
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answered by handygirl 3
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1. 2x (x being the number of students)
2. 25+8.5x (x being the hours spent on the court)
3. 1/2(x) (x being the distance)
4. (x + 10) / 24 (x is the number, 24 is the demoninator in the fraction)
5. 45x (x is how many hours)
Hope this helps.
2007-10-16 11:27:33
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answer #6
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answered by Anonymous
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Err.. Okay.
1. Define variables first.
L is last year's group. So the expression would be:
2L
2. Interesting. This can be made into a linear equation, but I will not do that.
H is the hours you play.
8.50h + 25
3. Easy..
D is the distance he, I assume, travelled to his original match.
1/2d
4. Okay:
X is the number.
(x + 10)/24
5. Hrm..
H is the hours he travelled.
45h
There.
2007-10-16 11:29:38
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answer #7
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answered by Anonymous
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1. x=last year's group, y=students interested y=2x
2. x=hours on court, y=total price 25+8.5x=y
3. x=distance traveled, y=distance to the match 1/2y=x
4. n=the number (x+10)/24
5. a=how far he traveled, h=hours traveling 45h=a
2007-10-16 11:34:55
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answer #8
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answered by Cuefrogger 2
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Let x = the number of this year's students
2x
Let x = hours of court time
$25 + $8.50x
Let x = distance tothe match
x/2
2007-10-16 11:30:22
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answer #9
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answered by towanda 7
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a million. The sum of t and 9 2. The quotient of c and 3 3. 10 under y 4. The quotient of x and 6 5. The quotient of a million and the made of four and w 6. The sum of a million and x 7. a million.a million under n IDK if quantity 5 is actual, yet i desire I did comfortable with something ;) stable luck in math!
2016-10-09 09:03:10
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answer #10
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answered by ? 3
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