please help with this
Given: 2052g of Al2(SO4)3
Find:
A- the # of moles
B- # of molecules
C- # of AL atoms
D- # of S atoms
please help me! thank you!
2007-10-16 10:52:15 · 2 answers · asked by =] 3 in Science & Mathematics ➔ Chemistry
A-2052/342.14 = 5.997 mols, which can be rounded to 6.
B- number of molecules is mols * 6.02 E 23. Answer is 3.612E24 or 3.612 x 10^24
C- number of AL atoms = number of molecules * 2 7.244E24 or 7.244 x 10^24
D- 1.0836E25 or 1.0836 x 10^25
2007-10-16 11:00:32 · answer #1 · answered by thundershock375 2 · 1⤊ 0⤋
Atomic weights: Al=27 S=32 O=16 Al2(SO4)3=342
2052gAl2(SO4)3 x 1molAl2(SO4)3/342gAl2(SO4)3 = 6.000 mole Al2(SO4)3
6.00molAl2(SO4)3 x 6.02x10^23moleculesAl2(SO4)3/1molAl2(SO4)3 = 3.612 x 10^24 molecules Al2(SO4)3
3.612x10^24moleculesAl2(SO4)3 x 2atomsAl/1moleculeAl2(SO4)3 = 7.224 x 10^24 atoms Al
3.612x10^24moleculesAl2(SO4)3 x 3atomsS/1moleculeAl2(SO4)2 = 1.084 x 10^25 atoms S
2007-10-16 18:15:21 · answer #2 · answered by steve_geo1 7 · 1⤊ 0⤋