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Please help!
I have some math homework I don't get.
These are on literal equations.

1. P=2L+2W, for W
Meaning isolate W.

2. Q=(C+D)/2, for D
Meaning isolate D.
By (C+D)/2, I mean (C+D) divided by 2

3. V=3k/T, for T
Meaning isolate T
By 3K/T, I mean 3K divided by T

4. Q=3A+5AC, for A
Meaning isolate A

5. Solve A=(1/2)AH-(1/2)BH, for H
Meaning isolate H
By (1/2), I mean one half.As in half of one, 0.5, etc.




Thank you so much for your help!

2007-10-16 09:58:29 · 5 answers · asked by Nouthesia 1 in Education & Reference Homework Help

5 answers

1. P=2L+2W, for W
P - 2L = 2W
(P - 2L)/2 = W

2. Q=(C+D)/2, for D
2Q = C+D
2Q - C = D

3. V=3k/T, for T
VT = 3k
T = 3k/V

4. Q=3A+5AC, for A
Q = A(3+5C)
A = Q/(5C + 3)

5. Solve A=(1/2)AH-(1/2)BH, for H
2A = AH - BH
2A = H(A-B)
H = 2A/(A-B)

2007-10-16 10:07:13 · answer #1 · answered by Steve A 7 · 0 0

a million) four.nine + four/17 = four.ninety + zero.23 = five.thirteen two) a million/two + a million/two = two/two = a million three) four/nine + a million/three = four/nine + three/nine = 7/nine = zero.seventy seven four) a million/two - four/17 = nine/34 17/34 - eight/34 = nine/34 nine/34 = nine/34 ==> CORRECT five) five/6 - five/17 = zero.eighty three - zero.29 = zero.fifty four 6) a million/two - three/eleven = five.five/eleven - three/eleven = two.five/eleven = zero.227 7) five/7 - three/thirteen = zero.seventy one - zero.23 = zero.forty eight eight) a million/two x three/thirteen = three/26 (a million x three) / (two x thirteen) = three/26 three / 26 = three/26 ==> CORRECT nine) a million/two x four/eleven = (a million x four) / (two x eleven) = four / 22 = two/eleven 10) four/7 x five/19 = (four x five) / (7 x 19) = 20 / forty five = four/nine eleven) a million/two x five/12 = (a million x five) / (two x 12) = five / 24 12) five/eight / (five/thirteen) = a million five/eight five/eight x thirteen/five = a million + five/eight (five x thirteen) / (eight x five) = eight/eight + five/eight sixty five / forty = thirteen/eight thirteen / eight = thirteen/eight ==> CORRECT thirteen) five/7 / (two/7) = five/7 x 7/two = (five x 7) / (7 x two) = 35 / 14 14) two/three / (a million/four) = two/three x four = eight / three 15) a million/two / (two/nine) = a million/two x nine/two = nine / (two x two) = nine / four In a few instances, whilst we've got a fragment it's bigger if we write it as a decimal (easily through dividing the numerator with the denominator). But in a few instances it is usually a bigger inspiration to paintings best with the numerators of the fractions (if they have got the equal denominator). Also, recollect that after dividing fractions you're truthfully multiplying the fraction through the reciprocal of the opposite one. Example: two/nine divided through five/eight ==> two/nine / (five/eight) divided (/) through five/eight ==> instances (x) eight/five (reciprocal of five/eight) two/nine / (five/eight) = two/nine x eight/five = (two x eight) / (nine x five) = sixteen / forty five NOTE: If the fraction may also be simplified, do it. In this example sixteen and forty five are not able to be simplified however they are able to be provided as a decimal (sixteen/forty five = zero.35). Hope this helped and well success! :)

2016-09-05 11:50:38 · answer #2 · answered by ? 4 · 0 0

1. W=(P-2L) / 2
How is it done?
P=2L+2W subtract 2L
P-2L=2W divide by 2
(P-2L) / 2=W

2. D=2Q-C
How is it done?
Q=(C+D) / 2 multiply by 2
2Q=C+D subtract C
2Q-C=D

3. T=3K / V
How is it done?
V=3K / T multiply by T
VT=3K divide by V
T=3K / V

4. A=Q / (3+5C)
How is it done?
Q=3A+5AC factor out A
Q=A(3+5C) divide by (3+5C)
Q / (3+5C)=A


5. H=A / (.5A-.5B) or H=A / [.5(A-B)]
How is it done?
A=.5AH-.5BH factor out H
A=H(.5A-.5B) divide by (.5A-.5B)
A / (.5A-.5B)=H factor out .5 (optional)
A / [.5(A-B)]=H

2007-10-16 10:16:58 · answer #3 · answered by LizzyLee 2 · 0 0

1. (P-2L)/2=W
2.2Q-C=D
3.(3K)/V=T

2007-10-16 10:08:45 · answer #4 · answered by kanwal 1 · 0 0

2.D=C-2Q

2007-10-16 10:10:19 · answer #5 · answered by Zaneli 3 · 0 0

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