Can anyone help me figure out this question, I just can't get it.?

Question

When ice at 0.0oC melts to liquid water at 0.0oC, it absorbs, 0.334 kJ of heat per gram. Suppose the heat needed to melt 32.0 g of ice is absorbed from the water contained in a glass. If this water has a mass of 0.610 kg and a temperature of 67.0oC, what is the final temperature of the water (in C)? (Note that you will also have 32.0 g of water at 0oC from the ice).

Answer 1

Just use algebra!
Thermal capacity of liquid water: 4.182 j/gC.
Let the final temperature of the water to be XoC.
32.0*(334+4.182*X) = 610*4.182*(67.0 - X).
Solve above equation to get X.